Instrumental Variables
Encouragement Designs, ITT, LATE, and Two-Stage Least Squares
State of the Union Address
The Selection Problem
- The headline is about State of the Union watchers, not a random sample.
- When the president is a Democrat, Democrats are more likely to watch.
- Controlling for party isn’t enough: Republicans who did watch differ from typical Republicans.
Visualizing the Problem (and Solution)
- D_i (treatment): Watched the State of the Union Address.
- Y_i (outcome): Felt proud or optimistic afterward.
- U_i (confounder): Party ID, political interest (unobserved factors that drive both watching and pride).
- Z_i (instrument): Randomly encouraged to watch.
Randomizing the Encouragement
Compliance
Compliers: take treatment when encouraged and do not take treatment when not encouraged. [D_i \mid Z_i = 1] = 1 \ \text{and} \ [D_i \mid Z_i = 0] = 0
But…some people do not comply.
- Always-takers: [D_i \mid Z_i = 1] = [D_i \mid Z_i = 0] = 1
- Never-takers: [D_i \mid Z_i = 1] = [D_i \mid Z_i = 0] = 0
- Defiers: [D_i \mid Z_i = 1] = 0 and [D_i \mid Z_i = 0] = 1
The treatment effect can only be assessed for compliers.
We Don’t See the Counterfactual
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D_i = 1 (takes treatment)
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D_i = 0 (no treatment)
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Z_i = 1 (encouraged)
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complier or always-taker
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defier or never-taker
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Z_i = 0 (not encouraged)
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defier or always-taker
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complier or never-taker
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Some Assumptions
- Ignorability of the instrument: (Y_i^1, Y_i^0) \perp Z_i
- Exclusion restriction: Z (instrument) only affects Y (outcome) through D (treatment). We cannot test the exclusion restriction. It must be defended theoretically.
- No weak instruments (relevance): \mathbb{E}[ D_i | Z_i = 1] - \mathbb{E}[ D_i | Z_i = 0] \neq 0
- No defiers (monotonicity).
Intent-to-Treat Effect
- Effect of being encouraged to take the treatment \mathbb{E}[Y_i \mid Z_i = 1] - \mathbb{E}[Y_i \mid Z_i = 0]
- \frac{1+1+1+0+0}{5} - \frac{1+1+0+0+0}{5} = \frac{3}{5} - \frac{2}{5} = 0.2
- Equivalent to a regression of Y on Z.
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id
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z
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d
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y
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1
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1
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1
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1
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2
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1
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1
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1
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3
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1
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1
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1
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4
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1
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0
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0
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5
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1
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1
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0
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6
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0
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1
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1
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7
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0
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0
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1
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8
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0
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0
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0
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9
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0
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0
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0
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10
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0
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0
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0
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Why This “Works”
- Z (encouragement) is randomly assigned.
- Exclusion restriction ensures any change in Y caused by Z operates entirely through D (no other pathways).
- If Z is relevant/not weak, then some proportion of our sample consists of compliers.
- Compliers drive the ITT. Always-takers and never-takers contribute nothing to the effect, but don’t distort its direction.
- There are no defiers (they cannot flip the sign of our estimate).
Two Questions, Two Estimands
- The ITT tells us: what happens if we run an encouragement campaign?
- Useful for a policymaker deciding whether to send the mailer.
- The problem: most people’s behavior didn’t change (always-takers and never-takers are in the ITT).
- If you want to know what watching the speech actually does, the ITT underestimates.
- What we want: the effect for people who only watched because we encouraged them, aka the Local Average Treatment Effect (LATE).
Decomposing the ITT
ITT = ITT_c \times \Pr(c) + ITT_a \times \Pr(a) + ITT_n \times \Pr(n) + ITT_d \times \Pr(d)
ITT = ITT_c \times \Pr(c) + ITT_a \times \Pr(a) + ITT_n \times \Pr(n) + ITT_d \times 0 \;\;\text{(no defiers)}
ITT = ITT_c \times \Pr(c) + 0 \times \Pr(a) + 0 \times \Pr(n) + 0 \times \Pr(d) \;\;\text{(exclusion restriction)}
\therefore ITT = ITT_c \times \Pr(c) \;\Rightarrow\; ITT_c = LATE = \frac{ITT}{\Pr(c)}
Estimating Pr(compliers)
- We need \Pr(c) to recover the LATE, but we cannot observe types directly.
\mathbb{E}[D \mid Z = 1] = \Pr(c) + \Pr(a) \quad \text{(compliers and always-takers both take treatment)}
\mathbb{E}[D \mid Z = 0] = \Pr(a) \quad \text{(only always-takers take treatment)}
\therefore \; \mathbb{E}[D \mid Z = 1] - \mathbb{E}[D \mid Z = 0] = \Pr(c)
- The same as regressing D on Z.
Calculating the LATE
ITT = \mathbb{E}[Y \mid Z = 1] - \mathbb{E}[Y \mid Z = 0] = 0.2
Using type values from the table and ITT: LATE = \frac{ITT}{\Pr(c)} = \frac{0.2}{(6/10)} = 0.33
Ignoring “type,” use the formula from previous slide: \frac{ITT}{\Pr(c)} = \frac{ITT}{\mathbb{E}[D \mid Z = 1] - \mathbb{E}[D \mid Z = 0]} = \frac{0.2}{\frac{4}{5} - \frac{1}{5}} = \frac{0.2}{0.6} = 0.33
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id
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z
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d
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type
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y
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1
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1
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1
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c
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1
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2
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1
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1
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c
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1
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3
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1
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1
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c
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1
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4
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1
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0
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n
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0
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5
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1
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1
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a
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0
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6
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0
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1
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a
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1
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7
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0
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0
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c
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1
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8
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0
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0
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c
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0
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9
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0
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0
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c
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0
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10
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0
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0
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n
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0
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Two-Stage Least Squares
Recover the LATE using two regressions chained together:
- First stage: regress D on Z to isolate variation in treatment driven by instrument.
- Second stage: regress Y on the “fitted values,” \hat{D}, from stage one.
- The stage-two coefficient on \hat{D} is the LATE.
First Stage
- Regress treatment D on the instrument Z.
lm(d ~ z, data = df)
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Term
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Estimate
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(Intercept)
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0.2
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z
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0.6
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- The Z coefficient is \Pr(c).
- The fitted values are 0.8 for those encouraged and 0.2 for those not encouraged.
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id
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z
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d
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D̂
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y
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1
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1
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1
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0.8
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1
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2
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1
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1
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0.8
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1
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3
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1
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1
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0.8
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1
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4
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1
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0
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0.8
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0
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5
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1
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1
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0.8
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0
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6
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0
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1
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0.2
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1
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7
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0
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0
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0.2
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1
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8
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0
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0
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0.2
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0
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9
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0
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0
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0.2
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0
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10
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0
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0
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0.2
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0
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Second Stage
- Regress outcome Y on the fitted treatment values \hat{D} from the first stage.
lm(y ~ d_hat, data = df)
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Term
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Estimate
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(Intercept)
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0.333
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d_hat
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0.333
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- The \hat{D} coefficient (0.33) is the LATE.
Some Finer Points
- Causal effect measured only for compliers, not an average treatment effect.
- The complier population may be small, limiting the precision of the LATE.
- Individual compliance types cannot be identified.
Which Effect to Estimate?
Both!
- ITT: Because not everyone complies, it gives us an idea of how a policy works in the real world.
- LATE: A more targeted estimate of how the treatment works for those whose treatment status changes because of the instrument.
It’s Not Just Randomized Experiments
- Does having more children lead women to leave the labor force?
- Instrument: having two same-sex children (Angrist and Evans 1998).
- Does police presence on the street reduce crime?
- Instrument: mayoral elections (Levitt 1997).
Florida 2018 and What Comes After